Optimal. Leaf size=138 \[ \frac {2 \left (1-a^2 x^2\right )}{45 a^2}+\frac {\left (1-a^2 x^2\right )^2}{60 a^2}+\frac {8 x \tanh ^{-1}(a x)}{45 a}+\frac {4 x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)}{45 a}+\frac {x \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)}{15 a}-\frac {\left (1-a^2 x^2\right )^3 \tanh ^{-1}(a x)^2}{6 a^2}+\frac {4 \log \left (1-a^2 x^2\right )}{45 a^2} \]
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Rubi [A]
time = 0.06, antiderivative size = 138, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 4, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {6141, 6089,
6021, 266} \begin {gather*} \frac {\left (1-a^2 x^2\right )^2}{60 a^2}+\frac {2 \left (1-a^2 x^2\right )}{45 a^2}+\frac {4 \log \left (1-a^2 x^2\right )}{45 a^2}-\frac {\left (1-a^2 x^2\right )^3 \tanh ^{-1}(a x)^2}{6 a^2}+\frac {x \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)}{15 a}+\frac {4 x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)}{45 a}+\frac {8 x \tanh ^{-1}(a x)}{45 a} \end {gather*}
Antiderivative was successfully verified.
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Rule 266
Rule 6021
Rule 6089
Rule 6141
Rubi steps
\begin {align*} \int x \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^2 \, dx &=-\frac {\left (1-a^2 x^2\right )^3 \tanh ^{-1}(a x)^2}{6 a^2}+\frac {\int \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x) \, dx}{3 a}\\ &=\frac {\left (1-a^2 x^2\right )^2}{60 a^2}+\frac {x \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)}{15 a}-\frac {\left (1-a^2 x^2\right )^3 \tanh ^{-1}(a x)^2}{6 a^2}+\frac {4 \int \left (1-a^2 x^2\right ) \tanh ^{-1}(a x) \, dx}{15 a}\\ &=\frac {2 \left (1-a^2 x^2\right )}{45 a^2}+\frac {\left (1-a^2 x^2\right )^2}{60 a^2}+\frac {4 x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)}{45 a}+\frac {x \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)}{15 a}-\frac {\left (1-a^2 x^2\right )^3 \tanh ^{-1}(a x)^2}{6 a^2}+\frac {8 \int \tanh ^{-1}(a x) \, dx}{45 a}\\ &=\frac {2 \left (1-a^2 x^2\right )}{45 a^2}+\frac {\left (1-a^2 x^2\right )^2}{60 a^2}+\frac {8 x \tanh ^{-1}(a x)}{45 a}+\frac {4 x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)}{45 a}+\frac {x \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)}{15 a}-\frac {\left (1-a^2 x^2\right )^3 \tanh ^{-1}(a x)^2}{6 a^2}-\frac {8}{45} \int \frac {x}{1-a^2 x^2} \, dx\\ &=\frac {2 \left (1-a^2 x^2\right )}{45 a^2}+\frac {\left (1-a^2 x^2\right )^2}{60 a^2}+\frac {8 x \tanh ^{-1}(a x)}{45 a}+\frac {4 x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)}{45 a}+\frac {x \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)}{15 a}-\frac {\left (1-a^2 x^2\right )^3 \tanh ^{-1}(a x)^2}{6 a^2}+\frac {4 \log \left (1-a^2 x^2\right )}{45 a^2}\\ \end {align*}
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Mathematica [A]
time = 0.03, size = 82, normalized size = 0.59 \begin {gather*} \frac {-14 a^2 x^2+3 a^4 x^4+4 a x \left (15-10 a^2 x^2+3 a^4 x^4\right ) \tanh ^{-1}(a x)+30 \left (-1+a^2 x^2\right )^3 \tanh ^{-1}(a x)^2+16 \log \left (1-a^2 x^2\right )}{180 a^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.62, size = 120, normalized size = 0.87
method | result | size |
derivativedivides | \(\frac {\frac {\arctanh \left (a x \right )^{2} a^{6} x^{6}}{6}-\frac {a^{4} x^{4} \arctanh \left (a x \right )^{2}}{2}+\frac {a^{2} x^{2} \arctanh \left (a x \right )^{2}}{2}-\frac {\arctanh \left (a x \right )^{2}}{6}+\frac {\arctanh \left (a x \right ) a^{5} x^{5}}{15}-\frac {2 a^{3} x^{3} \arctanh \left (a x \right )}{9}+\frac {a x \arctanh \left (a x \right )}{3}+\frac {a^{4} x^{4}}{60}-\frac {7 a^{2} x^{2}}{90}+\frac {4 \ln \left (a x -1\right )}{45}+\frac {4 \ln \left (a x +1\right )}{45}}{a^{2}}\) | \(120\) |
default | \(\frac {\frac {\arctanh \left (a x \right )^{2} a^{6} x^{6}}{6}-\frac {a^{4} x^{4} \arctanh \left (a x \right )^{2}}{2}+\frac {a^{2} x^{2} \arctanh \left (a x \right )^{2}}{2}-\frac {\arctanh \left (a x \right )^{2}}{6}+\frac {\arctanh \left (a x \right ) a^{5} x^{5}}{15}-\frac {2 a^{3} x^{3} \arctanh \left (a x \right )}{9}+\frac {a x \arctanh \left (a x \right )}{3}+\frac {a^{4} x^{4}}{60}-\frac {7 a^{2} x^{2}}{90}+\frac {4 \ln \left (a x -1\right )}{45}+\frac {4 \ln \left (a x +1\right )}{45}}{a^{2}}\) | \(120\) |
risch | \(\frac {\left (a^{2} x^{2}-1\right )^{3} \ln \left (a x +1\right )^{2}}{24 a^{2}}-\frac {\left (15 a^{6} x^{6} \ln \left (-a x +1\right )-6 a^{5} x^{5}-45 x^{4} \ln \left (-a x +1\right ) a^{4}+20 a^{3} x^{3}+45 x^{2} \ln \left (-a x +1\right ) a^{2}-30 a x -15 \ln \left (-a x +1\right )\right ) \ln \left (a x +1\right )}{180 a^{2}}+\frac {\ln \left (-a x +1\right )^{2} a^{4} x^{6}}{24}-\frac {a^{3} x^{5} \ln \left (-a x +1\right )}{30}-\frac {\ln \left (-a x +1\right )^{2} a^{2} x^{4}}{8}+\frac {a^{2} x^{4}}{60}+\frac {a \,x^{3} \ln \left (-a x +1\right )}{9}+\frac {x^{2} \ln \left (-a x +1\right )^{2}}{8}-\frac {7 x^{2}}{90}-\frac {x \ln \left (-a x +1\right )}{6 a}-\frac {\ln \left (-a x +1\right )^{2}}{24 a^{2}}+\frac {4 \ln \left (a^{2} x^{2}-1\right )}{45 a^{2}}+\frac {49}{540 a^{2}}\) | \(248\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.26, size = 93, normalized size = 0.67 \begin {gather*} \frac {{\left (a^{2} x^{2} - 1\right )}^{3} \operatorname {artanh}\left (a x\right )^{2}}{6 \, a^{2}} + \frac {{\left (3 \, a^{2} x^{4} - 14 \, x^{2} + \frac {16 \, \log \left (a x + 1\right )}{a^{2}} + \frac {16 \, \log \left (a x - 1\right )}{a^{2}}\right )} a + 4 \, {\left (3 \, a^{4} x^{5} - 10 \, a^{2} x^{3} + 15 \, x\right )} \operatorname {artanh}\left (a x\right )}{180 \, a} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.35, size = 116, normalized size = 0.84 \begin {gather*} \frac {6 \, a^{4} x^{4} - 28 \, a^{2} x^{2} + 15 \, {\left (a^{6} x^{6} - 3 \, a^{4} x^{4} + 3 \, a^{2} x^{2} - 1\right )} \log \left (-\frac {a x + 1}{a x - 1}\right )^{2} + 4 \, {\left (3 \, a^{5} x^{5} - 10 \, a^{3} x^{3} + 15 \, a x\right )} \log \left (-\frac {a x + 1}{a x - 1}\right ) + 32 \, \log \left (a^{2} x^{2} - 1\right )}{360 \, a^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 0.51, size = 133, normalized size = 0.96 \begin {gather*} \begin {cases} \frac {a^{4} x^{6} \operatorname {atanh}^{2}{\left (a x \right )}}{6} + \frac {a^{3} x^{5} \operatorname {atanh}{\left (a x \right )}}{15} - \frac {a^{2} x^{4} \operatorname {atanh}^{2}{\left (a x \right )}}{2} + \frac {a^{2} x^{4}}{60} - \frac {2 a x^{3} \operatorname {atanh}{\left (a x \right )}}{9} + \frac {x^{2} \operatorname {atanh}^{2}{\left (a x \right )}}{2} - \frac {7 x^{2}}{90} + \frac {x \operatorname {atanh}{\left (a x \right )}}{3 a} + \frac {8 \log {\left (x - \frac {1}{a} \right )}}{45 a^{2}} - \frac {\operatorname {atanh}^{2}{\left (a x \right )}}{6 a^{2}} + \frac {8 \operatorname {atanh}{\left (a x \right )}}{45 a^{2}} & \text {for}\: a \neq 0 \\0 & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 473 vs.
\(2 (119) = 238\).
time = 0.41, size = 473, normalized size = 3.43 \begin {gather*} \frac {4}{45} \, a {\left (\frac {2 \, {\left (\frac {10 \, {\left (a x + 1\right )}^{2}}{{\left (a x - 1\right )}^{2}} - \frac {5 \, {\left (a x + 1\right )}}{a x - 1} + 1\right )} \log \left (-\frac {a x + 1}{a x - 1}\right )}{\frac {{\left (a x + 1\right )}^{5} a^{3}}{{\left (a x - 1\right )}^{5}} - \frac {5 \, {\left (a x + 1\right )}^{4} a^{3}}{{\left (a x - 1\right )}^{4}} + \frac {10 \, {\left (a x + 1\right )}^{3} a^{3}}{{\left (a x - 1\right )}^{3}} - \frac {10 \, {\left (a x + 1\right )}^{2} a^{3}}{{\left (a x - 1\right )}^{2}} + \frac {5 \, {\left (a x + 1\right )} a^{3}}{a x - 1} - a^{3}} + \frac {30 \, {\left (a x + 1\right )}^{3} \log \left (-\frac {a x + 1}{a x - 1}\right )^{2}}{{\left (\frac {{\left (a x + 1\right )}^{6} a^{3}}{{\left (a x - 1\right )}^{6}} - \frac {6 \, {\left (a x + 1\right )}^{5} a^{3}}{{\left (a x - 1\right )}^{5}} + \frac {15 \, {\left (a x + 1\right )}^{4} a^{3}}{{\left (a x - 1\right )}^{4}} - \frac {20 \, {\left (a x + 1\right )}^{3} a^{3}}{{\left (a x - 1\right )}^{3}} + \frac {15 \, {\left (a x + 1\right )}^{2} a^{3}}{{\left (a x - 1\right )}^{2}} - \frac {6 \, {\left (a x + 1\right )} a^{3}}{a x - 1} + a^{3}\right )} {\left (a x - 1\right )}^{3}} - \frac {\frac {2 \, {\left (a x + 1\right )}^{3}}{{\left (a x - 1\right )}^{3}} - \frac {7 \, {\left (a x + 1\right )}^{2}}{{\left (a x - 1\right )}^{2}} + \frac {2 \, {\left (a x + 1\right )}}{a x - 1}}{\frac {{\left (a x + 1\right )}^{4} a^{3}}{{\left (a x - 1\right )}^{4}} - \frac {4 \, {\left (a x + 1\right )}^{3} a^{3}}{{\left (a x - 1\right )}^{3}} + \frac {6 \, {\left (a x + 1\right )}^{2} a^{3}}{{\left (a x - 1\right )}^{2}} - \frac {4 \, {\left (a x + 1\right )} a^{3}}{a x - 1} + a^{3}} - \frac {2 \, \log \left (-\frac {a x + 1}{a x - 1} + 1\right )}{a^{3}} + \frac {2 \, \log \left (-\frac {a x + 1}{a x - 1}\right )}{a^{3}}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 1.00, size = 111, normalized size = 0.80 \begin {gather*} \frac {x^2\,{\mathrm {atanh}\left (a\,x\right )}^2}{2}-\frac {{\mathrm {atanh}\left (a\,x\right )}^2}{6\,a^2}-\frac {7\,x^2}{90}+\frac {4\,\ln \left (a^2\,x^2-1\right )}{45\,a^2}+\frac {a^2\,x^4}{60}+\frac {x\,\mathrm {atanh}\left (a\,x\right )}{3\,a}-\frac {2\,a\,x^3\,\mathrm {atanh}\left (a\,x\right )}{9}+\frac {a^3\,x^5\,\mathrm {atanh}\left (a\,x\right )}{15}-\frac {a^2\,x^4\,{\mathrm {atanh}\left (a\,x\right )}^2}{2}+\frac {a^4\,x^6\,{\mathrm {atanh}\left (a\,x\right )}^2}{6} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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